review updates to E0311 description
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@ -14,33 +14,25 @@ fn with_restriction<'a, T: 'a>(x: &'a ()) -> &'a () {
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```
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Why doesn't this code compile? It helps to look at the lifetime bounds that are
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automatically adding by the compiler. For more details see the Rust
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Documentation for Lifetime Elision:
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https://doc.rust-lang.org/reference/lifetime-elision.html.
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automatically added by the compiler. For more details see the documentation for
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[lifetime elision]( https://doc.rust-lang.org/reference/lifetime-elision.html).
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There are two lifetimes being passed into the `no_restriction()` function: one
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associated with the generic type `T` parameter and the other with the input
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argument `x`. The compiler does not know which of these lifetimes can be
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assigned to the output reference, so we get an error.
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The compiler elides the lifetime of `x` and the return type to some arbitrary
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lifetime `'anon` in `no_restriction()`. The only information available to the
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compiler is that `'anon` is valid for the duration of the function. When
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calling `with_restriction()`, the compiler requires the completely unrelated
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type parameter `T` to outlive `'anon` because of the `T: 'a bound` in
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`with_restriction()`. This causes an error because `T` is not required to
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outlive `'anon` in `no_restriction()`.
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One way to "fix" this code would be to remove the generic type argument `T`.
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In this case, the lifetime elision works because there is a single input
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lifetime, which is associated with `x`.
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If `no_restriction()` were to use `&T` instead of `&()` as an argument, the
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compiler would have added an implied bound [implied
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bound](https://rust-lang.github.io/rfcs/2089-implied-bounds.html), causing this
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to compile.
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```
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fn no_restriction(x: &()) -> &() {
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with_restriction(x)
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}
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This error can be resolved by explicitly naming the elided lifetime for `x` and
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then explicily requiring that the generic parameter `T` outlives that lifetime:
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fn with_restriction<'a>(x: &'a ()) -> &'a () {
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x
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}
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```
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The "correct" way to resolve this error is to explicitly tell the compiler
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which input lifetime should be assigned to the output. In this case we give
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both the generic type `T` parameter and the argument `x` the same lifetime
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requirement as the output reference, producing a working version of the code:
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```
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fn no_restriction<'a, T: 'a>(x: &'a ()) -> &'a () {
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with_restriction::<T>(x)
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