Skip binary tidy check when on Windows Linux Subsystem
While it's possible that other linux systems will include "Microsoft" in their /proc/version, this is deemed unlikely, and since this is a tidy check, will likely be caught by buildbot/travis either way.
This commit is contained in:
parent
05c2fdd64f
commit
50dad3f1fd
1 changed files with 11 additions and 0 deletions
|
@ -24,9 +24,20 @@ pub fn check(_path: &Path, _bad: &mut bool) {}
|
|||
#[cfg(unix)]
|
||||
pub fn check(path: &Path, bad: &mut bool) {
|
||||
use std::fs;
|
||||
use std::io::Read;
|
||||
use std::process::{Command, Stdio};
|
||||
use std::os::unix::prelude::*;
|
||||
|
||||
if let Ok(mut file) = fs::File::open("/proc/version") {
|
||||
let mut contents = String::new();
|
||||
file.read_to_string(&mut contents).unwrap();
|
||||
// Probably on Windows Linux Subsystem, all files will be marked as
|
||||
// executable, so skip checking.
|
||||
if contents.contains("Microsoft") {
|
||||
return;
|
||||
}
|
||||
}
|
||||
|
||||
super::walk(path,
|
||||
&mut |path| super::filter_dirs(path) || path.ends_with("src/etc"),
|
||||
&mut |file| {
|
||||
|
|
Loading…
Add table
Reference in a new issue